In a reaction, a + b + c→ d, it is found that the reaction is first order in terms of a and second order in terms of b and half order in terms of

c. what happens to the rate if the concentrations of a and c are doubled and b remains the same?

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27 March, 00:31

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Kyle Garrison · Answer 1

Rate=[a] * ([b]^2) * ([c]^ (1/2) ]

rate=[2a] * ([b]^2) * ([2c]^ (1/2) ] = 2 * (2^ (1/2) [a] * ([b]^2) * ([c]

it increases times 2 * (2^ (1/2) = 2√2

In a reaction, a + b + c→ d, it is found that the reaction is first order in terms of a and second order in terms of b and half order in terms ofc. what happens to the rate if the concentrations of a and c are doubled and b remains the same?