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6 March, 19:14

What volume of a 0.160 m solution of koh must be added to 450.0 ml of the acidic solution to completely neutralize all of the acid?

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  1. 6 March, 19:39
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    An acidic solution is 0.1M in HCl and 0.2 H2so4. volume is equal to no of moles divided by molarity.

    number of moles of HCl is 450ml x 0.1 divided by 1000 which is equal to 0.045 moles

    volume of HCl is therefore 0.45 divided by 0.16 which is 2.81 litres

    Number of moles of H2so4 is 450ml x 0.2 divided by 1000 which is equal to 0.09 moles

    volume of H2SO4 IS 0.09 divided by 0.16 which is equal to 0.56 litres
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