What volume of a 3.00 M KI stock solution would you use to make 0.195 L of a 1.25 M KI solution?

For the purpose we will use solution dilution equation:

c1xV1=c2xV2

Where, c1 - concentration of stock solution; V1 - a volume of stock solution needed to make the new solution; c2 - final concentration of new solution; V2 - final volume of new solution.

c1 = 3.00 M

c2 = 1.25 M

V1 = ?

V2 = 0.195 L

When we plug values into the equation, we get following:

3 x V1 = 1.25 x 0.195

V1 = 0.08 L