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26 January, 07:35

The solubility of calcium sulfate at 30°c is 0.209 g/100 ml solution. calculate its ksp.

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  1. 26 January, 07:49
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    Answer is: Ksp for calcium sulfate is 2.36·10⁻⁴.

    Balanced chemical reaction (dissociation):

    CaSO₄ (s) → Ba²⁺ (aq) + SO₄²⁻ (aq).

    m (CaSO₄) = 0.209 g.

    n (CaSO₄) = m (CaSO₄) : M (CaSO₄).

    n (CaSO₄) = 0.209 g : 136.14 g/mol.

    n (CaSO₄) = 0.00153 mol.

    s (CaSO₄) = n (CaSO₄) : V (CaSO₄).

    s (CaSO₄) = 0.00153 mol : 0.1 L = 0.0153 M.

    Ksp = [Ca²⁺] · [SO₄²⁻].

    [Ca²⁺] = [SO₄²⁻] = s (CaSO₄).

    Ksp = (0.0153 M) ² = 2.36·10⁻⁴.
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