How many carbon atoms are present in 1.84 moles of C2H6O?

Question

Aniya Dominguez

Chemistry

12 September, 18:53

How many carbon atoms are present in 1.84 moles of C2H6O?

+2

Answers (2)

Know the Answer?

Reuben Mercer · Answer 1

Answer is: there are 2,208·10²⁴ cabron atoms.

n (C₂H₆O) = 1,84 mol.

In one mol of C₂H₆O, there is two mol of carbon.

n (C) = 2 · n (C₂H₆O).

n (C) = 2 · 1,84 mol.

n (C) = 3,68 mol.

N (C) = n (C) · Na.

N (C) = 3,68 mol · 6·10²³ 1/mol.

N (C) = 2,208·10²⁴.

Na - Avogadro number.

Geovanni Duran · Answer 2

2.22x10^24 carbon atoms. Each C2H6O molecule has 2 carbon atoms, so there is 1.84 * 2 = 3.68 moles of carbon atoms. To convert from moles to individual atoms, just multiply by Avogadro's number, so 3.68 * 6.0221409x10^23 = 2.21615x10^24 Rounding to 3 significant digits gives 2.22x10^24 carbon atoms.