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29 November, 18:12

Nahco3 is the active ingredient in baking soda. how many grams of oxygen are in 0.72 g of nahco3?

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  1. 29 November, 18:19
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    M (O) = M x n

    M (O) = 16g/mol

    n (O) = 3 x n (NaHCO3)

    n (NaHCO3) = m/M

    m (NaHCO3) = 0.72g

    M (NaHCO3) = 23 + 1 + 14 + 16 x 3 = 86g/mol

    n (NaHCO3) = 0.72/86 = 0.008372mol

    n (O) = 3 x 0.008372 = 0.02512

    m (O) = 16 x 0.02512 = 0.402g
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