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10 August, 20:26

The gas in a 250. mL piston experiences a change in pressure from 1.00 atm to 4.45 atm. What is the new volume (in mL) assuming the moles of gas and temperature are held constant

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  1. 10 August, 20:48
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    56.2 mL

    Explanation:

    Given data

    Initial volume (V₁) : 250 mL Initial pressure (P₁) : 1.00 atm Final volume (V₂) : ? Final pressure (P₂) : 4.45 atm

    Assuming the gas has an ideal behavior, we can find the final volume using Boyle's law.

    P₁ * V₁ = P₂ * V₂

    V₂ = P₁ * V₁/P₂

    V₂ = 1.00 atm * 250 mL / 4.45 atm

    V₂ = 56.2 mL
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