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15 March, 16:13

What mass of barium nitrate is dissolved in 21.29 mL of a 3.38 M solution?

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  1. 15 March, 16:14
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    18.81 g

    Explanation:

    We are given;

    Volume of Barium nitrate as 21.29 mL or 0.02129 L Molarity of Barium nitrate as 3.38 M

    We are required to determine the mass of Barium nitrate

    Step 1: Determine the number of moles of Barium nitrate

    Number of moles = Molarity * Volume

    = 3.38 M * 0.02129 L

    = 0.07196 moles

    Step 2: Determine the mass of Barium nitrate

    We know that;

    Mass = Number of moles * Molar mass

    Molar mass of Barium Nitrate is 261.337 g/mol

    Therefore;

    Mass of barium nitrate = 0.07196 moles * 261.337 g/mol

    = 18.8058 g

    = 18.81 g

    Thus, the mass of barium nitrate dissolved is 18.81 g
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