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25 May, 18:09

Determine the molar solubility of agi in pure water. ksp (agi) = 8.51 * 10-17.

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  1. 25 May, 18:30
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    When the salt AgI dissolves in water it dissociates as follows;

    AgI - - - > Ag⁺ + I⁻

    molar solubility is the number of moles that are dissolved in 1 L of solution.

    If molar solubility of AgI is x, then molar solubility of Ag⁺ is x and I⁻ is x.

    the formula for solubility product constant - ksp of AgI is given below

    ksp = [Ag⁺][I⁻]

    ksp = (x) (x)

    ksp = 8.51 x 10⁻¹⁷

    therefore,

    x² = 8.51 x 10⁻¹⁷

    x = 9.22 x 10⁻⁹

    since molar solubility of AgI is x, then molar solubility of AgI is 9.22 x 10⁻⁹ M
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