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8 February, 02:05

A solution is made by mixing equal masses of methanol, CH 4 O, CH4O, and ethanol, C 2 H 6 O. C2H6O. Determine the mole fraction of each component to at least three significant figures.

X meth = X eth = Xeth=

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  1. 8 February, 02:32
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    Answer: The mole fraction of methanol

    Xmeth = 0.59

    The mole fraction of ethanol

    Xeth = 0.41

    Explanation:

    Mole fraction of a component can be determined by:

    Xi = moles of i / total moles of the components the components

    Where i indicates the component

    An equal mass of 100.0g is assumed for both methanol and ethanol

    Molar mass of Methanol (CH4O)

    = (1*12) + (4*1) + (1*16) = 32g/mol

    Mole of Methanol = mass of methanol / molar mass of methanol

    =100/32 = 3.13mol.

    Molar mass of ethanol (C2H6O)

    = (2*12) + (6*1) + (1*16) = 46.0g/mol

    Mole of ethanol = 100/46

    = 2.17mol.

    Mole fraction of methanol (Xmeth)

    = moles of methanol / total moles

    Xmeth = 3.13 / (3.13+2.17)

    Xmeth = 0.59

    Mole fraction of ethanol (Xeth)

    = moles of ethanol / total moles

    = 2.17 / ((3.13+2.17)

    Xeth = 0.41
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