How many liters of O2 gas will be produced at STP from 4 moles of KC1O3

V = 134.5 L

Explanation:

Given dа ta:

Number of moles of KClO₃ = 4 mol

Litters of oxygen produced at STP = ?

Solution:

Chemical equation:

2KClO₃ → 2KCl + 3O₂

Now we will compare the moles of KClO₃ with oxygen.

KClO₃ : O₂

2 : 3

4; 3/2*4 = 6 mol

Litters of oxygen at STP:

PV = nRT

V = nRT/P

V = 6 mol * 0.0821 atm. L/mol. K * 273 K / 1atm

V = 134.5 L / 1

V = 134.5 L