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29 June, 08:47

What is the value of q when the solution contains 2.00*10-2 m ca2 + and 3.00*10-2m cro42-? express your answer numerically?

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  1. 29 June, 09:01
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    Answer is: value of Q is 6·10⁻⁴.

    Chemical reaction: CaCrO₄ (s) → Ca²⁺ (aq) + CrO₄²⁻ (aq).

    [Ca²⁺] = 0,02 M.

    [CrO₄²⁻] = 0,03 M.

    Q = [Ca²⁺] · [CrO₄²⁻].

    Q = 0,02 M · 0,03 M.

    Q = 0,0006 M².

    Q is the solubility product when the system is not at equilibrium.
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