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29 June, 08:24

What volume 12.6 M HCL must be added to enough water to prepare 5.00 litters of 3.00 M HCL?

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  1. 29 June, 08:33
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    To solve this problem, we shall use the role;

    M1V1 = M2V2

    M1: is the molarity of the solution before dilution.

    V1: is the volume of the solution that we need to dilute.

    M2: is the molarity of the solution after dilution.

    V2: is the volume of the solution after dilution.

    By substitution;

    12*V1 = 3*5

    V1 = 1.25 litters.
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