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22 March, 04:42

0.0400 M solution of HClO2, pH = 1.80 solve for Ka

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  1. 22 March, 05:06
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    Ka for weak acids is - - - > Ka = (X) ² / (initial - X)

    initial = 0.0400 M

    to find X, you can find the H concentration using pH

    [H+] = 10^-pH

    [H+] = 10^-1.80 = 0.016 which is X

    ka = (0.016) ² / (0.0400 - 0.016) = 0.011
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