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28 March, 12:05

The decomposition of SOCl2 is first-order in SOCl2. If the half-life for the reaction is 4.1 hr, how long would it take for the concentration of SOCl2 to drop from 0.36 M to 0.045 M?

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  1. 28 March, 12:09
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    4.1 h = 14760 s

    t 1/2 = ln 2 / k

    k = rate reaction = 4.97 x 10^-5

    ln 0.045 / 0.36 = - 4.97 x 10^-5 t

    2.08 = 4.97 x 10^-5 t

    t = 41839.9 s = 11 h 37 min 19 s
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