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7 February, 23:35

How many moles of KCl are required to prepare 1.50 L of 5.4 M KCl?

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  1. 7 February, 23:40
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    5.4 M = moles of solute / 1.50 L

    Multiply both sides by 1.50 L to isolate moles of solute on the right.

    8.1 mol = moles of solute
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