1. If 6 moles of KNO3 should be produced in a reaction, but only 4.78 mol KNO3 are produced, what is the % yield?

79.7%

Explanation:

Percent yield of reaction is defined as the ratio between theoretical yield of a reaction and actual yield obtained.

In the problem, theoretical yield are 6 moles of KNO₃ and actual yield are 4.78 moles. Thus, percent yield is:

4.78 mol / 6 mol * 100 = 79.7%