How many atoms of carbon are in 0.425 g of ibuprofen?

Question

Douglas Parrish

Chemistry

24 December, 21:24

How many atoms of carbon are in 0.425 g of ibuprofen?

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Answers (1)

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Tyson Wolfe · Answer 1

Answer is: 1,6·10²².

Molecular formula of ibuprofen is C₁₃H₁₈O₂.

m (C₁₃H₁₈O₂) = 0,425 g.

n (C₁₃H₁₈O₂) = m (C₁₃H₁₈O₂) : m (C₁₃H₁₈O₂)

n (C₁₃H₁₈O₂) = 0,425g : 206,3 g/mol = 0,002mol.

n (C) : n (C₁₃H₁₈O₂) = 13 : 1

n (C) = 0,026 mol.

N (C) = n (C) · Na = 0,026 mol · 6·10²³ 1/mol = 1,6·10²².

Na - Avogadro number.