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3 October, 15:53

What is the mass of oxygen that can be produced from 2.79 moles of lead (ll) nitrate

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  1. 3 October, 16:14
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    1.38 moles of oxygen

    Explanation:

    Thermal decomposition of Lead (II) nitrate is shown by the balanced equation below;

    2Pb (NO₃) ₂ → 2PbO + 4NO₂ + O₂

    The mole ration of Lead (II) nitrate to oxygen is 2: 1

    Therefore 2.76 moles of Lead (II) nitrate will lead to production of? moles of oxygen;

    2: 1

    2.76: x

    Cross-multiply;

    2x = 2.76 * 1

    x = 2.76 / 2

    x = 1.38
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