A thief plans to steal a gold sphere with the radius of 28.9cm from a museum. If the gold has a density of 19.3 g/cm^3 what is the mass of the sphere in pounds? (Volume of a sphere is V = (4/3) pi r^3) Is the thief likely to be able to walk off with gold sphere unassisted?

Question

Kingston Vega

Chemistry

16 September, 08:27

A thief plans to steal a gold sphere with the radius of 28.9cm from a museum. If the gold has a density of 19.3 g/cm^3 what is the mass of the sphere in pounds? (Volume of a sphere is V = (4/3) pi r^3) Is the thief likely to be able to walk off with gold sphere unassisted?

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Ronnie Haas · Answer 1

First you have to plug the radius (28.9 cm) in the equation for volume, so you would have V = (4/3) * pi * (28.9) ^3 (which means cubed) to get 101107.2126 cm^3 for volume, next use that in the formula m = d*V = 19.3g/cm^3 * 101107.2126 to get 1,951,369.203g to convert to pounds you multiply that by 0.00220462262 or 0.002 for short to get 4,302.03 pounds

Unless he can carry 4k pounds, I don't think he getting away.