If 0.545J of heat leads to a 0.892 degree C change, what mass of water is present?

I got. 146 g of water

Explanation:

Refer to this equation:

Q = mcΔt

Q=.545 J

c = 4.186 J/g

Δt=.892

plug in values:

.545 J = m (4.186 J/g) (.892°C)

simplify:

.545 J = m (3.734 J/g°C)

.146 g