363 mL of a solution of NaOH is diluted to a final of 1400mL and and the new molarity is 0.286 calculate the original molarity of the base Report your answer with 4 decimal places

Question

Gianna Anderson

Chemistry

23 April, 07:12

363 mL of a solution of NaOH is diluted to a final of 1400mL and and the new molarity is 0.286 calculate the original molarity of the base Report your answer with 4 decimal places

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Answers (1)

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Alannah · Answer 1

The original molarity is 1,1030M.

Explanation:

A dilution consists of the decrease of concentration of a substance in a solution (the higher the volume of the solvent, the lower the concentration).

We use the formula for dilutions:

C1 x V1 = C2 x V2

C1 = (C2 xV2) / V1

C1 = (1400 ml x 0,286 M) / 363 ml

C1=1,1030 M