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1 November, 08:15

An aqueous nacl solution is made using 112 g of nacl diluted to a total solution volume of 1.00 l. calculate the molarity, molality, and mass percent of the solution. (assume a density of 1.08 g>m

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  1. 1 November, 08:22
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    Q1)

    molarity is defined as the number of moles of solute in 1 L of solution.

    the NaCl solution volume is 1.00 L

    number of moles NaCl = NaCl mass present / molar mass of NaCl

    NaCl moles = 112 g / 58.5 g/mol = 1.91 mol

    the number of moles of NaCl in 1.00 L of solution is - 1.91 mol

    therefore molarity of NaCl is 1.91 M

    Q2)

    molality is defined as the number of moles of solute in 1 kg of solvent.

    density is mass per volume.

    density of the solution is 1.08 g/mL.

    therefore mass of the solution is = density x volume

    mass = 1.08 g/mL x 1000 mL = 1080 g

    since we have to find the moles in 1 kg of solvent

    mass of solvent = 1080 g - 112 g = 968 g

    number of moles of NaCl in 968 g of solvent - 1.91 mol

    therefore number of NaCl moles in 1000 g - (1.91 mol / 968 g) x 1000 g/kg = 1.97 mol/kg

    molality of NaCl solution is 1.97 mol/kg

    Q3)

    mass percentage is the percentage of mass of solute by total mass of the solution

    mass percentage of solution = mass of solute / total mass of the solution

    mass of solute = 112 g

    total mass of solution = 1080 g

    mass % of NaCl = 112 g / 1080 g x 100%

    therefore mass % of NaCl = 10.4 %

    answer is 10.4 %
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