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14 April, 14:46

If 63.99 mL of Ba (OH) 2 is required to neutralize 56.3 mL of 0.0410 molar HCl, what is the molarity of the Ba (OH) 2?

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  1. 14 April, 14:49
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    0.0181 M

    Explanation:

    Let's consider the following neutralization reaction.

    2 HCl + Ba (OH) ₂ → BaCl₂ + 2 H₂O

    56.3 mL of 0.0410 M HCl react. The moles of HCl are:

    0.0563 L * 0.0410 mol/L = 2.31 * 10⁻³ mol

    The molar ratio of HCl to Ba (OH) ₂ is 2:1. The moles of Ba (OH) ₂ are:

    1/2 * 2.31 * 10⁻³ mol = 1.16 * 10⁻³ mol

    There are 1.16 * 10⁻³ mol of Ba (OH) ₂ in 63.99 mL. The molarity of Ba (OH) ₂ is:

    1.16 * 10⁻³ mol / 63.99 * 10⁻³ L = 0.0181 M
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