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19 January, 22:09

According to the following reaction, how many moles of calcium carbonate are necessary to form 0.906 moles carbon dioxide?

calcium carbonate (s) calcium oxide (s) + carbon dioxide (g)

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  1. 19 January, 22:26
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    0.906 moles of calcium carbonate needed to produced 0.906 moles of carbon dioxide.

    Explanation:

    Given dа ta:

    Moles of carbon dioxide produced = 0.906 mol

    Moles of calcium carbonate needed = ?

    Solution:

    Chemical equation:

    CaCO₃ → CaO + CO₂

    Now will compare the moles of carbon dioxide with calcium carbonate:

    CO₂ : CaCO₃

    1 : 1

    0.906 : 0.906

    So 0.906 moles of calcium carbonate needed to produced 0.906 moles of carbon dioxide.
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