What is the mass of 2.56 * 10-4 moles of Fe2O3? : 6.23 * 105 159.6 g 1.60 * 0-6 g 4.09 * 10-2 g

4.09 * 10⁻² g

Solution:

As we know that,

1 mol of Fe₂O₃ is equal to = 159.69 g

So,

2.56 * 10⁻⁴ mol will be equal to = X g

Solving for X,

X = (159.69 g * 2.56 * 10⁻⁴ mol) : 1 mol

X = 0.04088 g

Or,

X = 0.049 g

Or,

X = 4.09 * 10⁻² g