Suppose that a solid cube of some material floats on the surface of an oil puddle at a service station with 75.1 % of its volume submerged. The density of the oil is 923 kg/m 3. What is the density of the cube's material

Answer: density of material pm = 693.2kg/m^3

Explanation:

Using Archimedes principle.

The buoyancy force equals the weight of material submerged which equals the weight liquid displaced.

Fb = Wm = Wl

I. e

Wm = Wl

pm. Vm. g = pl. Vl. g

pm. Vm = pl. Vl

pm/pl = Vl/Vm

Where; pm and pl are the density of material and liquid oil respectively.

Vm and Vl are the volume of material and volume liquid displaced respectively.

g is the acceleration due to gravity

Fb is the buoyancy force

Wm and Wl are the material weight and liquid displaced weight respectively

Given that the material displaced 75.1% of the volume of the liquid oil

VI/Vm = 0.751

pm/pl = 0.751

pm = 0.751pl

density of oil is 923kg/m^3

pm = 0.751 * 923

pm = 693.2kg/m^3