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7 November, 03:47

How many grams of mercury are needed to react completely with 157g of sulfur to form hgs?

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  1. 7 November, 04:08
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    To solve this we need to balance the equations first.

    So Hg + S - - > HgS is balanced

    One mole of Hg requires one mole of S to form one mole of HgS.

    Number of moles of Sulphur = mass / molar mass = 157/32 = 4.906

    So 4.90 moles of S reacts with 4.90 moles of Hg.

    Hence there are 4.90 moles of 4.90 of Hg.

    Mass = number of moles * molar mass of Hg

    Mass = 4.906 * 200.59 = 982.891g
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