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7 November, 05:15

How many atoms of phosphorus are in 9.20 mol of copper (II) phosphate?

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  1. 7 November, 05:42
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    The number of atoms of phosphorus in copper (II) phosphate [Cu3 (PO4) 2] is determined by multiplying first 9.20 by 2 since there are two phosphorus atoms in the compound and multiplying again with Avogadro's number. The answer is 1.108 x 10^25 atoms.
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