Starting with 1.5052g of BaCl2•2H2O and excessH2SO4, how many grams of BaSO4 can be formed?

1.5052g BaCl2.2H2O = > 1.5052g / 274.25 g/mol = 0.0054884 mol

=> 0.0054884 mol Ba

This means that at most 0.0054884 mol BaSO4 can form since Ba is the limiting reagent.

0.0054884 mol BaSO4 = > 0.0054884 mol * 233.39 g/mol = 1.2809 g BaSO4