What is the molarity of a naoh solution if 11.9 ml of a 0.220 m h2so4 solution is required to neutralize a 25.0-ml sample of the naoh solution?

0.355M x 0.0282L = 0.01 moles of H2SO4. Remember sulphuric acid is diprotic so it will release 2 from each molecule.

So moles of protons = 0.01 x 2 = 0.02 moles of H+

For neutralization: moles H + = moles OH-

Therefore moles of NaOH = 0.02

conc = moles / volume

Conc NaOH = 0.02 / 0.025L = 0.8M