A chemist determines by measurements that 0.0900 moles of bromine liquid participate in a chemical reaction. Calculate the mass of bromine liquid that participates. Be sure your answer has the correct number of significant digits.

14.4 grams of bromine liquid participate on the reaction

Explanation:

Bromine liquid is also a diatomic molecule as the gas form.

Br₂

Molar mass = 159.8 g/m

Molar mass. mol = mass

159.8 g/m. 0.0900 mol = 14.4 grams

There will participate 14.4 grams of bromine

Explanation:

Step 1: Data given

Liquid bromine is Br2

Numbers of moles of bromine liquid = 0.0900 moles

Molar mass of Br = 79.9 g/mol

Molar mass of Br2 = 2 * 79.9 = 159.8 g/mol

Step 2: Calculate the mass of bromine that will participate

Mass = moles * molar mass

Mass bromine = 0.0900 moles * 159.8 g/mol

Mass bromine = 14.4 grams

There will participate 14.4 grams of bromine