Hydrogen chloride and oxygen react to form chlorine and water, like this:

4 HCl (g) + O2 (9) - --> 2 Cl2 (g) + 2 H20 (g)

Write the pressure equilibrium constant expression for this reaction.

Question

Paxton Dominguez

Chemistry

22 November, 10:17

Hydrogen chloride and oxygen react to form chlorine and water, like this:

4 HCl (g) + O2 (9) - --> 2 Cl2 (g) + 2 H20 (g)

Write the pressure equilibrium constant expression for this reaction.

+4

Answers (1)

Know the Answer?

Paola Gibson · Answer 1

Kp = ((pH2O) ² * (pCl2) ²] / ((pO2) (pHCl) ^4)

Explanation:

Step 1: data given

Hydrogen chloride = HCl

oxygen = O2

chlorine = Cl2

water = H2O

Step 2: The balanced equation

4 HCl (g) + O2 (g) ⇒ 2 Cl2 (g) + 2 H20 (g)

Step 3: Define the pressure equilibrium constant

Kc = [[H2O]²*[Cl2]²] / [[O2][HCl]^4]

Kp = ((pH2O) ² * (pCl2) ²] / ((pO2) (pHCl) ^4)

⇒ with pH2O = the partial pressure of H2O

⇒ with pCl2 = the partial pressure of Cl2

⇒ with pO2 = the partial pressure of O2

⇒ with pHCl = the partial pressure of HCl

Hydrogen chloride and oxygen react to form chlorine and water, like this:4 HCl (g) + O2 (9) - --> 2 Cl2 (g) + 2 H20 (g)Write the pressure equilibrium constant expression for this reaction.

Hydrogen chloride and oxygen react to form chlorine and water, like this:

4 HCl (g) + O2 (9) - --> 2 Cl2 (g) + 2 H20 (g)

Write the pressure equilibrium constant expression for this reaction.