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22 November, 17:27

Find the concentration of chloride ions in a solution that is 0.110 m in sodium chloride (nacl) and 0.11 m in magnesium chloride (mgcl2).

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  1. 22 November, 17:29
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    (.11M NaCl) * (1 mol Cl / 1 mol NaCl) =.11M from NaCl

    (.11M MgCl2) * (2 mol Cl / 1 mol MgCl2) =.055M from MgCl2

    .11M +.055M = 0.165M of Cl
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