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30 September, 11:12

How many moles of s are needed to combine with 0.208 mol al to give al2s3?

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Answers (1)
  1. 30 September, 11:33
    0
    0.312 mol of S

    Solution:

    The Balance Chemical equation is as follow,

    2 Al + 3 S → Al₂S₃

    According to this equation,

    2 moles of Al required = 3 moles of S

    Then,

    0.208 moles of Al will require = X moles of S

    Solving for X,

    X = (0.208 mol * 3 mol) : 2 mol

    X = 0.312 mol of S

    Result:

    0.312 moles of S are needed to combine with 0.208 mol Al to give Al₂S₃.
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