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16 July, 00:09

The rate constant is 0.556 L mol-1 s-1 at some temperature. If the initial concentration of NOBr in the container is 0.32 M, how long will it take for the concentration to decrease to 0.039 M

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  1. 16 July, 00:28
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    12.96 seconds

    Explanation:

    Assuming the reaction follows a first order

    Rate = K[NOBr] = change in concentration of NOBr/time

    K = 0.556 L mol^-1 s^-1

    Change in concentration of NOBr = 0.32M - 0.039M = 0.281M

    0.281/t = 0.556*0.039

    t = 0.281/0.021684 = 12.96 seconds
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