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15 October, 08:45

An electrical heater is used to add 21.75 kJ of heat to aconstant-volume calorimeter. The temperature of the calorimeterincreases by 4.18 oC. When 3.00 g of butanol (C4H9OH) is burned in the same calorimeter, the temperature increases by 20.81 oC. Calculate themolar heat of combustion for butanol.

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  1. 15 October, 09:05
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    The molar heat of combustion for butanol is 2.7 * 10³ kJ/mol

    Explanation:

    Step 1: Data given

    Temperature change = 4.18 °C

    mass of butanol = 3.00 grams

    When butanol is burned Temperature change = 20.81 °C

    Step 2: Calculate Ccalorimeter

    Ccal = 21750J / 4.18 °C = 5203.35 J / °C

    Step 3: Calculate heat generated

    Heat generated = 20.81 °C * 5203.35 J/°C = 108281.71 J = 108.28 kJ

    Step 4: Calculate moles of butanol

    Number of moles = mass / molar mass

    Number of moles = 3 grams / 74.123 g/mol = 0.04 moles

    Step 5: Calculate Molar heat of combustion

    Molar heat of combustion = 108.28 kJ / 0.04 moles = 2707 kJ / mol

    The molar heat of combustion for butanol is 2.7 * 10³ kJ/mol
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