2. 10 kg of food at a moisture content of 320% dry basis is dried to 50% wet basis. Calculate the amount of water removed

Question

Noe Montoya

Chemistry

15 September, 06:24

2. 10 kg of food at a moisture content of 320% dry basis is dried to 50% wet basis. Calculate the amount of water removed

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Answers (1)

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Zaiden · Answer 1

3.6 kg of water is being removed.

Explanation:

Initial weight of food sample = 10 kg

The dry weight is 32% means it has 3.2 kg of dry mass and 6.8 kg of water.

On heating the sample becomes 50% wet basis it means the sample contains 50% dry weight. The earlier dry mass was 3.2 kg, and there will be no change in it. Thus the mass of water will also be 3.2 kg (50%).

The initial mass of water = 6.8 kg

the final mass of water = 3.2 kg

The mass of water removed = 6.8 - 3.2 = 3.6 kg