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20 July, 23:02

How many L of CO2 at STP could be produced from the reaction of 2 L of CH4 at STP with 2 L of O2 at STP?

CH4+2O2-2H2O+CO2

A 1L

B 2L

C 3L

D 4L

+2
Answers (1)
  1. 20 July, 23:23
    0
    Option A = 1 L

    Explanation:

    Given dа ta:

    Volume of CH₄ = 2 L

    Volume of O₂ = 2 L

    Volume of CO₂ = ?

    Solution:

    First of all we will write balance chemical equation.

    CH₄ + 2O₂ → 2H₂O + CO₂

    Number of moles of CH₄:

    PV = nRT

    n = PV/RT

    n = 1 atm. 2 L / 0.0821 atm. L. mol⁻¹. K⁻¹ * 273.15 k⁻¹

    n = 2 atm. L / 22.43 atm. L. mol⁻¹

    n = 0.09 mol

    Number of moles of O₂:

    PV = nRT

    n = PV/RT

    n = 1 atm. 2 L / 0.0821 atm. L. mol⁻¹. K⁻¹ * 273.15 k⁻¹

    n = 2 atm. L / 22.43 atm. L. mol⁻¹

    n = 0.09 mol

    Now we compare the moles of O₂ and CH₄ with CO₂ from balance chemical equation

    CH₄ : CO₂

    1 : 1

    0.09 : 0.09

    O₂ : CO₂

    2 : 1

    0.09 : 1/2*0.09 = 0.045 mol

    Volume of CO₂

    PV = nRT

    V = nRT / P

    V = 0.045 mol * 0.0821 atm. L. mol⁻¹. K⁻¹ * 273.15 k⁻¹ / 1 atm

    V = 1.0092 L

    Which is approximately equal to 1 L.
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