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28 May, 09:16

A reaction produces 10.5 L if oxygen, but was supposed to produce 1 mol of oxygen. What is the percent yield? (One mole of any gas occupies 22.4 L under certain conditions of temperature and pressure. Assume those conditions for this question)

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  1. 28 May, 09:17
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    To answer this item, we assume that oxygen behaves ideally such that it is able to fulfill the following equation,

    PV = nRT

    If we are to retain constant the variable n and V.

    The percent yield can therefore be solved through the following calculation,

    n = (10.5 L) / (22.4 L) x 100%

    Simplifying,

    n = 46.875%

    Answer: 48.87%
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