PV = k, where Pis pressure, Vis volume, and k is a constant

Question 1

Suppose you have a gas in a container being pressed down by a piston. The initial volume of the gas is 5.0 m3 and

the pressure is 7.5 mmHg. If the volume decreases to 4.0 m, what is the pressure? (The product of the volume and

pressure remain constant.)

(5.0 m) (7.5 mmHg) = (P) (4.0 m)

Question

Smokey

Chemistry

28 May, 09:26

PV = k, where Pis pressure, Vis volume, and k is a constant

Question 1

Suppose you have a gas in a container being pressed down by a piston. The initial volume of the gas is 5.0 m3 and

the pressure is 7.5 mmHg. If the volume decreases to 4.0 m, what is the pressure? (The product of the volume and

pressure remain constant.)

(5.0 m) (7.5 mmHg) = (P) (4.0 m)

+3

Answers (1)

Know the Answer?

Tori Hubbard · Answer 1

9.38mmHg

Explanation:

V₁ = 5m³

P₁ = 7.5mmHg

V₂ = 4.0m³

P₂ = ?

Applying Boyle's law,

The volume of a fixed mass of of gas is inversely proportional to its pressure as long as temperature is kept constant.

P = k / V

P₁ * V₁ = P₂ * V₂

v₂ = (p₁ * v₁) / v₂

V₂ = (5.0 * 7.5) / 4.0

v₂ = 9.375 ≈ 9.38mmHg

The new volume of the gas is 9.38mmHg