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3 May, 20:41

A 0.15 m solution of a weak acid is 3.0 dissociated. calculate ka

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  1. 3 May, 21:06
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    If x is H + then x/0.15 = 0.03 and x = 0.0045 M and

    Ka = x^2 / (0.15 - x) = 0.0045^2 / (0.15 - 0.0045) = 1.39 x 10^-4
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