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9 August, 18:46

If the coal is burned in a power plant that uses 2000 tons of coal per day, what mass of calcium oxide is required daily to eliminate the sulfur dioxide? How many grams of calcium sulfite are produced daily by this power plant?

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  1. 9 August, 19:02
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    There is 86.87 tons of CaO required and there will be 186.15 tons of calcium sulfite produced.

    Explanation:

    Step 1: The balanced equation

    S (s) + O2 (g) → SO2 (l)

    SO2 (g) + CaO (s) → CaSO3 (s)

    This means 1 mol S = 1 mol SO2 = 1 mol CaO = 1 mole CaSO3

    Step 2: Given data

    1 ton = 907.185Kg

    Molar mass of sulfur = 32.065 g/mole

    Molar mass of Calcium oxide = 56.078 g/mol e

    Molar mass of calcium sulfite = 120.17 g/mole

    Step 3: Calculate mass of coal

    2000 tons = 1802370 Kg

    Step 4: Calculate mass of sulfur:

    ⇒ A particular coal contains 2.5% sulfur by mass.

    1802370 Kg * 2.5% = 45059.25 Kg = 45059250 grams

    Step 5: Calculate moles of Sulfur

    Moles of sulfur = mass of sulfur / Molar mass of sulfur

    Moles sulfur = 45059250 grams / 32.065g/mole = 1405247.2 moles

    This means there is also produced 1405247.2 moles of Calcium oxide (CaO).

    This means there is 1405247.2 * 56.078 = 78803452.5 grams = 78.803.4525 Kg = 86.8659 tons of CaO

    Step 6: Calculate mass of Calcium sulfite

    1405247.2 moles * 120.17 g/moles = 168868556.024 g = 168868.556 kg = 186.15 tons

    There is 86.87 tons of CaO required and there will be 186.15 tons of calcium sulfite produced.
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