A solenoid 2 cm long consists of 5653 loops of wire. If the magnetic field inside the solenoid is 4 T, what is the magnitude of the current that flows through it? A solenoid 2 cm long consists of 5653 loops of wire. If the magnetic field inside the solenoid is 4 T, what is the magnitude of the current that flows through it? 140 A 9.1*10-2 A 11 A 2.0 A

Question

Kadence Parker

Chemistry

8 January, 15:21

A solenoid 2 cm long consists of 5653 loops of wire. If the magnetic field inside the solenoid is 4 T, what is the magnitude of the current that flows through it? A solenoid 2 cm long consists of 5653 loops of wire. If the magnetic field inside the solenoid is 4 T, what is the magnitude of the current that flows through it? 140 A 9.1*10-2 A 11 A 2.0 A

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Answers (1)

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Munchkin · Answer 1

11 A

Explanation:

The magnetic field inside a solenoid can be calculated by the equation:

B = μ * (N/L) * i

Where B is the magnetic field, μ is the magnetic permeability (which is 1.256x10⁻⁶ T/m. A at vacuum), N is the number os loops, L is the length of the solenoid (2 cm = 0.02 m), and i the current.

4 = 1.256x10⁻⁶ * (5653/0.02) * i

0.355i = 4

i ≅ 11 A