List the number of each type of atom on the right side of the equation hbr (aq) + 2naoh (aq) →2nabr (s) + h2o (l)

On the basis of the given unbalanced equation, that is:

HBr (aq) + 2NaOH (aq) → 2NaBr (s) + H2O (l)

On the right side of the equation, there are 2 atoms of sodium (Na), 2 atoms of bromine (Br), 2 atoms of hydrogen (H), and 1 atom of oxygen (O₂).

After balancing the equation correctly we get:

HBr (aq) + NaOH (aq) → NaBr (s) + H2O (l)

On the right side, one atom of Na, 1 atom of Br, 1 atom of H and one atom of O₂.

As per the given unbalanced equation:-

HBr (aq) + 2NaOH (aq) - -> 2NaBr (s) + H2O (l)

Na:-2

Br:-2

H: - 2

O: - 1

If correctly balanced then

HBr (aq) + NaOH (aq) - -> NaBr (s) + H2O (l)

Na:-1

Br:-1

H: - 2

O: - 1