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22 August, 00:55

At 25 °C, 1.00 mole of O2 gas was found to occupy a volume of

12.5 L at a pressure of 198 kPa. What is the value of the gas

constant in Lakpa?

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Answers (1)
  1. 22 August, 01:24
    0
    R = 8.3 LakPaK-1

    Explanation:

    Applying PV = nRT

    P = 198kPa, V = 12.5L, n = 1, T = 25+273 = 298K

    198*12.5 = 1*R * 298

    Simplify

    R = 8.3LkPa
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