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11 July, 13:21

Biphenyl, C 12 H 10, C12H10, is a nonvolatile, nonionizing solute that is soluble in benzene, C 6 H 6. C6H6. At 25 ∘ C, 25 ∘C, the vapor pressure of pure benzene is 100.84 Torr. What is the vapor pressure of a solution made from dissolving 19.0 g 19.0 g of biphenyl in 27.8 g 27.8 g of benzene?

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  1. 11 July, 13:34
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    Vapor pressure of solution = 75.02 Torr

    Explanation:

    Vapor pressure of pure solvent (P°) - Vapor pressure of solution = P°. Xm. i

    As the solute is nonvolatile and nonionizing, i = 1

    Let's determine the Xm (mole fraction)

    Moles of solute → 19 g. 1mol/154g = 0.123moles

    Moles of solvent → 27.8 g. 1mol / 78 g = 0.356 moles

    Total moles = 0.123 + 0.356 = 0.479

    Xm = 0.123 / 0.479 = 0.256

    Let's replace in the formula

    100.84 Torr - Vapor pressure of solution = 100.84 Torr. 0.256. 1

    Vapor pressure of solution = - (100.84 Torr. 0256 - 100.84 Torr) → 75.02Torr
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