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2 December, 19:06

How many grams of o2 are necessary to react with 212 G of mg 2mg+o2➡2mgo?

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  1. 2 December, 19:08
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    We are given an equation 2Mg+O2-> 2MgO and a starting chemical Mg of about 212 g. In order to solve for the amount of O2 needed, we need the molecular weight of Mg and O2.

    Molecular weight:

    Mg=24.305 g/mol

    O2=16 (2) = 32 g/mol

    Note that for every 1 mol of O2, the amount of Mg must be 2 mol.

    So,

    g O2 = 212 g Mg x1mo Mgl/24.305 g Mg x1mol O2 / 2 mol Mg x 32 g O2/mol O2

    gO2=139.56 g

    Therefore, 139.56 g of O2 is needed for every 212 g Mg.
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