Ask Question
29 June, 02:55

In Flask A, you reacted 7.23 g Mg with 1.05 mol HCl. In Flask B, you reacted 1.22 g Mg with 1.35 mol HCl. Which balloon will inflate the most?

+2
Answers (1)
  1. 29 June, 03:12
    0
    The reaction between Magnesium and Hydrogen Chloride is:

    Mg + 2 HCl → MgCl₂ + H₂

    The balloon will inflate because gas is liberated in the presence of H₂.

    Let's compute which of the reactants is limiting. The solution is as follows:

    Molar mass of Mg = 24.305 g/mol

    Molar mass of HCl = 36.45 g/mol

    Flask A:

    Moles HCl needed = 7.23 g Mg * (1 mol/24.305 g) * (2 mol HCl/1 mol Mg) = 0.595 moles

    Since the available mass of Mg needs 0.595 moles of HCl, and HCl has excess amounts of 1.05 moles, the excess reactant is HCl and the limiting reactant is Mg. So, let's base our production on Mg. The more H₂ produced, the bigger the balloon.

    Flask A:

    Moles H₂ produced = 7.23 g Mg * (1 mol/24.305 g) * (1 mol H₂/1 mol Mg) = 0.297 moles

    Flask B:

    Moles H₂ produced = 1.22 g Mg * (1 mol/24.305 g) * (1 mol H₂/1 mol Mg) = 0.05 moles

    Therefore, Flask A will inflate the most.
Know the Answer?
Not Sure About the Answer?
Find an answer to your question 👍 “In Flask A, you reacted 7.23 g Mg with 1.05 mol HCl. In Flask B, you reacted 1.22 g Mg with 1.35 mol HCl. Which balloon will inflate the ...” in 📗 Chemistry if the answers seem to be not correct or there’s no answer. Try a smart search to find answers to similar questions.
Search for Other Answers