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8 December, 22:23

What is the percent by mass of 5.0 g of nacl mixed with 80. g of water?

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  1. 8 December, 22:31
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    Mass of solute (m1) = 5.0 g NaCl

    mass of solvent (m2) = 80.0 g H2O

    T% = (m1 / m1 + m2) * 100

    T% = (5.0 / 5.0 + 80.0) * 100

    T% = (5.0 / 85.0) * 100

    T% = 0.0588 * 100

    T = 5.88%
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